Star_T
06-02-2004, 04:38 AM
how can I draw this in a picturebox???
y=3x²+2x+4
y=3x²+2x+4
Draw a curve?Star_T 06-02-2004, 04:38 AM how can I draw this in a picturebox??? y=3x²+2x+4 Iceplug 06-02-2004, 08:16 AM Use a For Loop. For X = 0 To PB.Width 'All values of pixels that fit nicely in the picturebox. Y = 3 * X * X + 2 * X + 4 'Function. GFXofPB.DrawLine(Pens.Black, Xold, Yold, X, Y) 'Draw a line connecting the two points. Next That'll just draw the positive part, and require a really tall textbox and a small width. For drawing part of the functions for negative values and for scaling, you'll need two more X and Y variables to go with the X and Y above... use one pair to determine where the line point will be drawn and the other pair to determine what the actual values are going to be used for X and Y. :) I discussed it in this thread (where I use GetPixel and SetPixel): http://www.xtremevbtalk.com/showthread.php?t=101869&highlight=Plotting+function P.S. For doing lines, you need to store the old position of the line, unless you use GFXtoPB.DrawLines() and store all of the function points into an array. Star_T 06-08-2004, 10:01 AM Thanks for that. and one mor question can I change coordinate system. y values increase downwards Is it posible to increase yvalues upwards. like real coordinate system Iceplug 06-08-2004, 10:40 AM Oh... sure. You can do something like this: Pretend that Y is the result that you got from the function... to make positive Y go up, you need to make Y negative. Then, if you add PB.Width, zero will be at the bottom of the picturebox. :) GY = PB.Width - Y That will put Y = 0 at the bottom of the textbox, and it will go to the top when Y increases. :) |
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