burningice96 06092005, 09:00 AM Hey... is there a function that will round down? Here's my situation.
I have an variable nIndex which is an Integer. I have another called CurrentRow which is also an integer (this program uses excel, but this isn't an excel related question, so I'm keeping it here.
Now then, when CurrentRow is between 120, nIndex should = 0, for 2140, it should equal 1, and so on.
The code I've used to do this is:
nIndex = CurrentRow / 20
However, when CurrentRow = 13, nIndex = 1. So it's rounding the 0.65 up to 1. Is there any way to get it to round down?
spikey_richie 06092005, 09:02 AM As far as I am aware, the round function is clever enough to do this for you:
Round Function
Description
Returns a number rounded to a specified number of decimal places.
Syntax
Round(expression [,numdecimalplaces])
The Round function syntax has these parts:
Part Description
expression Required.Numeric expression being rounded.
numdecimalplaces Optional. Number indicating how many places to the right of the decimal are included in the rounding. If omitted, integers are returned by the Round function.
Diurnal 06092005, 09:04 AM You could force integer math:
nIndex = Currentrow \ 20
TeraBlight 06092005, 09:06 AM Sounds like you want Int() or Fix() (equivalent for positive numbers)
Either of these will just chop off digits after the decimal point, so
0.999 > 0
1.000 > 1
burningice96 06092005, 09:07 AM Diurnal: That works perfectly. Thanks! :)
stevo 06092005, 11:48 AM correct me if im wrong but if Currentrow was to equal 20 then the result would be 1 using "nIndex = Currentrow \ 20". you need to minus 1 from the Currentrow first like this
nIndex = (Currentrow  1) \ 20
snarfblam 06092005, 04:22 PM correct me if im wrong but if Currentrow was to equal 20 then the result would be 1 using "nIndex = Currentrow \ 20". you need to minus 1 from the Currentrow first like this
nIndex = (Currentrow  1) \ 20
Quite right. With
nIndex = Currentrow \ 20
nIndex would equal 0 for 019, 1 for 2039, etc.
unclebill 06092005, 11:15 PM Try:nIndex = CurrentRow Mod 20
stevo 06102005, 01:56 AM unclebill, using Mod will only work on two numbers, 20 and 21. any other number will be wrong.
unclebill 06112005, 12:17 AM You're right. I had tested a couple of things and was looking at the results of one and thought it was Mod. Blew that one bad!unclebill, using Mod will only work on two numbers, 20 and 21. any other number will be wrong.
snarfblam 06112005, 10:34 AM Mod returns the remainder of a division.
0 mod 20 = 0
1 mod 20 = 1
...
19 mod 20 = 19
20 mod 20 = 0
21 mod 20 = 1
This is great for a "wraparound" effect, but you will certainly run into problems if you replace integer division with modulus.
TeraBlight 06112005, 10:54 AM Mod returns the remainder of a division.
0 mod 20 = 0
1 mod 20 = 1
...
19 mod 20 = 19
20 mod 20 = 0
21 mod 20 = 1
This is great for a "wraparound" effect, but you will certainly run into problems if you replace integer division with modulus.
Mod and Div are complementary in the sense that if you have one, you can construct the other  so, if you are in trapped in Bizarro World and all you HAVE is mod, you could always use
(x  (x mod 20)) / 20
to achieve integer division... :)
Tinman0330 06122005, 01:11 PM To force a number to round down:
Round(number  0.5, 0)
To force a number to round up:
Round(number + 0.5, 0)
Hope this helps!
DubbleClick 06122005, 02:04 PM Int() also works for rounding down.
stevo 06122005, 02:15 PM using Round() wont always work on whole numbers as it uses bankers rounding.
Int(number) 'down
Int(number) 'up
though none of these are any good for the original question :p
