positioning panels on form

Hi everyone.

Please excuse the cross-post. I accidentally posted this in the Legacy VB section, but I'm actually using .NET.... :rolleyes:

Anyway, here goes:

I have 5 panels on a form (this number can vary but the size of all the panels are the same) and I need to position them across the top of my windows form. The panels were created programmatically and I am positioning them via code also to allow for resizing.

I need one panel in the leftmost corner, one in the rightmost corner, and the remaining panels evenly spaced in between those two. I can't figure out an algorithm for this and am really hoping one of you can help me out. Thanks in advance.

What about the sizes on the panels? Are they all gonna have 20% width? or do some have fixed width?

Each panel has the same width?

The first panel's .Left goes to 0 (its leftmost)
The last panel's .Left should be F.ClientSize.Width - panel.width (F is the form, probably Me)
Therefore the other three panels should be evenly distributed from 0 to F.ClientSize.Width - panel.width.
Since you have three panels left over, you just have to subdivide the range into fours (accounts for the first one):
That means you take F.ClientSize.Width - panel.width and divide it by 4.

Next, you multiply by 1, 2, and 3 to get the panel locations:
panel1 .Left is F.ClientSize.Width - panel.width / 4
panel2 .Left is 2 * panel1. Left
panel3 is 3 * panel1
:)

Thank you! I was missing first panel. I kept dividing by 3 for the remaining panels instead of 4. Much thanks. :)